Pada lab ini ita akan belajar melakukan redistribute routing protocol RIP ke EIGRP. Berikut topologi yang akan kita gunakan pada lab ini.
|
Gambar 1 Topologi jaringan RIP & EIGRP |
Topologi diatas merupakan topologi yang sudah kita gunakan pada lab-lab sebelumnya. Selanjutnya pada lab ini kita hanya akan menambahkan IP pada interface loopback di R1 dan mengadvertise IP tersebut ke RIP.
R1(config)#int lo0
R1(config-if)#ip add 1.1.1.1 255.255.255.0
R1(config-if)#router rip
R1(config-router)#no auto-summary
R1(config-router)#version 2
R1(config-router)#network 1.1.1.0
Sekarang kita coba lihat tabel routing di R2 dan R3, apakah kedua router tersebut sudah memiliki informasi tentang network 1.1.1.0/24 ataukah belum
R2(config-router)#do sh ip ro
10.0.0.0/32 is subnetted, 6 subnets
D 10.10.10.1 [90/409600] via 23.23.23.3, 00:00:35, Ethernet0/1
D 10.10.10.2 [90/409600] via 23.23.23.3, 00:00:30, Ethernet0/1
D 10.10.10.3 [90/409600] via 23.23.23.3, 00:00:24, Ethernet0/1
D 10.10.10.4 [90/409600] via 23.23.23.3, 00:00:18, Ethernet0/1
D 10.10.10.5 [90/409600] via 23.23.23.3, 00:00:13, Ethernet0/1
D 10.10.10.6 [90/409600] via 23.23.23.3, 00:00:03, Ethernet0/1
12.0.0.0/8 is variably subnetted, 2 subnets, 2 masks
C 12.12.12.0/24 is directly connected, Ethernet0/0
23.0.0.0/8 is variably subnetted, 2 subnets, 2 masks
C 23.23.23.0/24 is directly connected, Ethernet0/1
R3(config-if)#do sh ip ro
10.0.0.0/32 is subnetted, 6 subnets
C 10.10.10.1 is directly connected, Loopback0
C 10.10.10.2 is directly connected, Loopback1
C 10.10.10.3 is directly connected, Loopback2
C 10.10.10.4 is directly connected, Loopback3
C 10.10.10.5 is directly connected, Loopback4
C 10.10.10.6 is directly connected, Loopback5
12.0.0.0/24 is subnetted, 1 subnets
D 12.12.12.0 [90/307200] via 23.23.23.2, 00:02:49, Ethernet0/0
23.0.0.0/8 is variably subnetted, 2 subnets, 2 masks
C 23.23.23.0/24 is directly connected, Ethernet0/0
Perhatikan bahwa R2 dan R3 belum mengetahui informasi tentang network 1.1.1.0/24, hal ini dikarenakan network ini berada di jaringan RIP sedangkan R2 dan R3 berada di jaringan EIGRP. Untuk mengatasi hal ini, kita harus melakukan redistribution di R1
R1(config-if)#router eigrp 1
R1(config-router)#redistribute rip metric 1 1 1 1 1
Sekarang kita coba lihat lagi tabel routing di R2 dan R3
R2(config-router)#do sh ip ro
1.0.0.0/24 is subnetted, 1 subnets
D EX 1.1.1.0 [170/2560025856] via 12.12.12.1, 00:00:44, Ethernet0/0
10.0.0.0/32 is subnetted, 6 subnets
D 10.10.10.1 [90/409600] via 23.23.23.3, 00:04:51, Ethernet0/1
D 10.10.10.2 [90/409600] via 23.23.23.3, 00:04:46, Ethernet0/1
D 10.10.10.3 [90/409600] via 23.23.23.3, 00:04:40, Ethernet0/1
D 10.10.10.4 [90/409600] via 23.23.23.3, 00:04:34, Ethernet0/1
D 10.10.10.5 [90/409600] via 23.23.23.3, 00:04:29, Ethernet0/1
D 10.10.10.6 [90/409600] via 23.23.23.3, 00:04:19, Ethernet0/1
12.0.0.0/8 is variably subnetted, 2 subnets, 2 masks
C 12.12.12.0/24 is directly connected, Ethernet0/0
23.0.0.0/8 is variably subnetted, 2 subnets, 2 masks
C 23.23.23.0/24 is directly connected, Ethernet0/1
R3(config-router)#do sh ip ro
1.0.0.0/24 is subnetted, 1 subnets
D EX 1.1.1.0 [170/2560051456] via 23.23.23.2, 00:01:14, Ethernet0/0
10.0.0.0/32 is subnetted, 6 subnets
C 10.10.10.1 is directly connected, Loopback0
C 10.10.10.2 is directly connected, Loopback1
C 10.10.10.3 is directly connected, Loopback2
C 10.10.10.4 is directly connected, Loopback3
C 10.10.10.5 is directly connected, Loopback4
C 10.10.10.6 is directly connected, Loopback5
12.0.0.0/24 is subnetted, 1 subnets
D 12.12.12.0 [90/307200] via 23.23.23.2, 00:07:03, Ethernet0/0
23.0.0.0/8 is variably subnetted, 2 subnets, 2 masks
C 23.23.23.0/24 is directly connected, Ethernet0/0
Perhatikan bahwa saat ini R2 dan R3 sudah memiliki informasi tentang network 1.1.1.0/24. Perhatikan label EX didepan route tersebut menandakan bahwa route tersebut didapat dari hasil redistribution dari routing protocol lain
Tidak ada komentar:
Posting Komentar
Komentar