Lab 39 - EIGRP Filtering IP Genap

Pada lab ini kita akan belajar tentang filtering di EIGRP. Berikut topologi yang akan kita gunakan pada lab ini.

Gambar 1 Topologi jaringan EIGRP

Tujuan kiat pada lab ini adalah agar R1 hanya memiliki informasi tentang IP yang ganjil saja pada tabel routingnya. 

Diasumsikan kita telah mengkonfigurasi EIGRP seperti topologi ditas dan R1 serta R2 sudah mememiliki informasi tentang seluruh IP Loopback R3 ditabel routingnya.

R1(config-router)#do sh ip ro 

      10.0.0.0/32 is subnetted, 6 subnets
D        10.10.10.1 [90/435200] via 12.12.12.2, 00:00:05, Ethernet0/0
D        10.10.10.2 [90/435200] via 12.12.12.2, 00:00:05, Ethernet0/0
D        10.10.10.3 [90/435200] via 12.12.12.2, 00:00:05, Ethernet0/0
D        10.10.10.4 [90/435200] via 12.12.12.2, 00:00:05, Ethernet0/0
D        10.10.10.5 [90/435200] via 12.12.12.2, 00:00:05, Ethernet0/0
D        10.10.10.6 [90/435200] via 12.12.12.2, 00:00:05, Ethernet0/0
      12.0.0.0/8 is variably subnetted, 2 subnets, 2 masks
C        12.12.12.0/24 is directly connected, Ethernet0/0
      23.0.0.0/24 is subnetted, 1 subnets
D        23.23.23.0 [90/307200] via 12.12.12.2, 00:01:08, Ethernet0/0

R2(config-router)#do sh ip ro 

      10.0.0.0/32 is subnetted, 6 subnets
D        10.10.10.1 [90/409600] via 23.23.23.3, 00:03:14, Ethernet0/1
D        10.10.10.2 [90/409600] via 23.23.23.3, 00:03:14, Ethernet0/1
D        10.10.10.3 [90/409600] via 23.23.23.3, 00:03:14, Ethernet0/1
D        10.10.10.4 [90/409600] via 23.23.23.3, 00:03:14, Ethernet0/1
D        10.10.10.5 [90/409600] via 23.23.23.3, 00:03:14, Ethernet0/1
D        10.10.10.6 [90/409600] via 23.23.23.3, 00:03:14, Ethernet0/1
      12.0.0.0/8 is variably subnetted, 2 subnets, 2 masks
C        12.12.12.0/24 is directly connected, Ethernet0/0
      23.0.0.0/8 is variably subnetted, 2 subnets, 2 masks
C        23.23.23.0/24 is directly connected, Ethernet0/1

Selanjutnya kita buat access list pada R2 agar R1 hanya memiliki informasi tentang IP ganjil saja.

R2(config)#access-list 1 permit 0.0.0.1 255.255.255.254
R2(config)#router eigrp 1
R2(config-router)#distribute-list 1 out eth0/0

Untuk pengujian kita coba lihat tabel routing di R1

R1(config-router)#do sh ip ro

      10.0.0.0/32 is subnetted, 3 subnets
D        10.10.10.1 [90/435200] via 12.12.12.2, 00:06:10, Ethernet0/0
D        10.10.10.3 [90/435200] via 12.12.12.2, 00:06:10, Ethernet0/0
D        10.10.10.5 [90/435200] via 12.12.12.2, 00:06:10, Ethernet0/0
      12.0.0.0/8 is variably subnetted, 2 subnets, 2 masks
C        12.12.12.0/24 is directly connected, Ethernet0/0

Perhatikan bahwa R1 hanya memiliki informasi tentang IP ganjil saja.

Selain mengkonfigurasi access list di R2 seperti diatas, kita juga bisa melakukan konfigurasi pada R1, hanya saja directionnya menjadi in. Kita hapus dulu konfigurasi access list di R2

R2(config-router)#no distribute-list 1 out eth0/0

Pastikan R1 sudah memiliki tabel routing yang lengkap lagi

R1(config-router)#do sh ip ro 

      10.0.0.0/32 is subnetted, 6 subnets
D        10.10.10.1 [90/435200] via 12.12.12.2, 00:00:05, Ethernet0/0
D        10.10.10.2 [90/435200] via 12.12.12.2, 00:00:05, Ethernet0/0
D        10.10.10.3 [90/435200] via 12.12.12.2, 00:00:05, Ethernet0/0
D        10.10.10.4 [90/435200] via 12.12.12.2, 00:00:05, Ethernet0/0
D        10.10.10.5 [90/435200] via 12.12.12.2, 00:00:05, Ethernet0/0
D        10.10.10.6 [90/435200] via 12.12.12.2, 00:00:05, Ethernet0/0
      12.0.0.0/8 is variably subnetted, 2 subnets, 2 masks
C        12.12.12.0/24 is directly connected, Ethernet0/0
      23.0.0.0/24 is subnetted, 1 subnets
D        23.23.23.0 [90/307200] via 12.12.12.2, 00:01:08, Ethernet0/0

Selanjutnya kita konfigurasi access list di R1

R1(config)#access-list 1 permit 0.0.0.1 255.255.255.254 
R1(config)#router eigrp 1
R1(config-router)#distribute-list 1 in eth0/0

Kita lihat tabel routing di R1 lagi

R1(config-router)#do sh ip ro

      10.0.0.0/32 is subnetted, 3 subnets
D        10.10.10.1 [90/435200] via 12.12.12.2, 00:06:10, Ethernet0/0
D        10.10.10.3 [90/435200] via 12.12.12.2, 00:06:10, Ethernet0/0
D        10.10.10.5 [90/435200] via 12.12.12.2, 00:06:10, Ethernet0/0
      12.0.0.0/8 is variably subnetted, 2 subnets, 2 masks
C        12.12.12.0/24 is directly connected, Ethernet0/0

Perhatikan bahwa hasilnya sama saja, yaitu R1 hanya akan memiliki informasi tentang IP ganjil saja pada tabel routingnya.